WebMar 16, 2016 · Try casting GetValues () return array to int s: string csvEnums = string.Join (",", Enum.GetValues (typeof (Bla)).Cast ()); The problem with GetValues () method is that returns an object of type Array, and there are no Join () overload that can process it correctly. Share Improve this answer Follow edited Mar 16, 2016 at 15:30 WebAs ed replied in the comment you can use the TextFieldParser class by passing the string in the constructor. Another way would be to use regular expressions to solve it.
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Webint [] arr = { 0, 1, 2, 3, 0, 1 }; // 012301 result = arr.ToString (); // comma-separated values // 0,1,2,3,0,1 result = arr.ToString (","); // left-padded to 2 digits // 000102030001 result = arr.ToString (2, '0'); Share Improve this answer edited Dec 2, 2009 at 1:48 answered Dec 1, 2009 at 1:03 Dr. Wily's Apprentice 10.2k 1 25 27 WebJan 15, 2024 · How to get a comma separated string from an array in C#? We can get a comma-separated string from an array using String.Join () method. string[] animals = { …
WebDec 1, 2008 · Join collection of objects into comma-separated string. In many places in our code we have collections of objects, from which we need to create a comma-separated list. The type of collection varies: it may be a DataTable from which we need a certain column, or a List, etc. Now we loop through the collection and use string ... WebJun 11, 2024 · CommaDelimitedStringCollection list = new CommaDelimitedStringCollection (); list.AddRange (new string [] { "Huey", "Dewey" }); list.Add ("Louie"); //list.Add (","); string s = list.ToString (); //Huey,Dewey,Louie Share Improve this answer Follow answered Feb 3, 2011 at 10:29 grysik44 233 2 7 Add a comment 5
WebApr 11, 2014 · I am getting the above array from this code. Array GoalIds = FilteredEmpGoals.Select (x => x.GoalId).Distinct ().ToArray (); I am trying to convert it to comma separated string like. 31935, 31940, 31976, 31993, 31994, 31995, 31990. To achieve this I tried. WebJan 30, 2024 · A Computer Science portal for geeks. It contains well written, well thought and well explained computer science and programming articles, quizzes and practice/competitive programming/company interview Questions.
WebApr 28, 2009 · This approach is very terse, and will throw a (not very informative) FormatException if the split string contains any values that can't be parsed as an int: int [] ints = str.Split (',').Select (s => int.Parse (s)).ToArray (); If you just want to silently drop any non-int values you could try this: private static int?
WebMay 26, 2010 · A solution would be to return integerArray.First () + integerArray.Skip (1).Aggregate ("", (accumulator, piece) => accumulator + "," + piece); – Razvan Jul 12, 2024 at 19:36 the more simpler way to get rid of the extra prepended comma is ::: integerArray.Aggregate ( "", (x, y) => string.Concat (x,",", y)).Substring (1) – OmGanesh birmingham grammar schools 11+ resultsWebUse LINQ Aggregate method to convert array of integers to a comma separated string. var intArray = new []{1,2,3,4}; string concatedString = intArray.Aggregate((a, b) =>Convert.ToString(a) + "," +Convert.ToString( b)); Response.Write(concatedString); … birmingham grammar schools 11+WebMay 19, 2024 · Table of Contents. #1: Define enum internal type. #2: Enums combination within the definition. #3: Serializer. #4: The real meaning of the Flags attribute. #5 Flags best practices. Wrapping up. In a previous article, I explained some details about enums in C#. Here I’ll talk about some other things that are useful and/or curious to know about ... birmingham grammar schools application onlineWebThe map function can be used to do the integer parsing in one line: str.split(',').map(parseInt) – Jud. Mar 6, 2014 at 21:12. 1. ... Pass your comma-separated string into this function and it will return an array, and if a comma-separated string is not found then it will return null. dan evans why is thatWebFeb 3, 2016 · IList listItem = Enumerable.Range (0, 100000).ToList (); var result = listItem.Aggregate (new StringBuilder (), (strBuild, intVal) => { strBuild.Append (intVal); strBuild.Append (","); return strBuild; }, (strBuild) => strBuild.ToString (0, strBuild.Length - 1)); Share Follow answered Oct 7, 2009 at 6:15 … dan e walls floridaWebI have a dynamic string: It looks like "1: Name, 2: Another Name" this. I want to split it and convert it to a List> or IEnmerable birmingham grammar schools forumdane walther